MATH 220 SUPPLEMENTAL NOTES 24

TRIPLE INTEGRALS IN RECTANGULAR COORDINATES

TRIPLE INTEGRALS

If F (x, y, z) is a function defined on a closed bounded region D in space (pretend that this region is a potato floating in space), then the integral of F over D maybe defined the following way. Partition a rectangular region containing D into rectangular cells by planes parallel to the coordinate planes. (Applying this concept to the potato, you first cut it into slices, then into french fries. The final cut makes rectangular cubes that resemble home fries.) Now, number these cells that lie inside D from 1 to n in some order. Pick a cell. This cell has side lengths Dx k, Dy k, and Dz k and volume DVk. Now choose a point (x k, y k, z k) in each cell and form the sum

If F is continuous and the bounding surface of D is made of smooth surfaces joined along continuous curves, then as Dx k, Dy k, and Dz k approach zero independently, the

Here are the properties of triple integrals.

1.

2.

3.

4.

5.

If D can be divided into a finite number of non-overlapping cells D1, D2, . . . D n, then

VOLUME OF A REGION IN SPACE

If F is the constant function whose value is 1, then

Therefore,

FACT:

The volume of a closed, bounded region D in space is

EXAMPLE 1:

Write six different iterated triple integral for the volume of the rectangular solid in the first octant bounded by the coordinate planes and the planes x = 2, y = 3, and z = 4. Evaluate one of the integrals.

SOLUTION:

x goes between 0 and 2. y goes between 0 and 3, and z goes between 0 and 4.

EXAMPLE 2:

Write six different iterated triple integrals for the volume of the tetrahedron cut from the first octant by the plane 4x + 2y + 6z = 12. Evaluate one of the integrals.

SOLUTION:

EXAMPLE 3:

Find the volume of the wedge cut from the cylinder x 2 + y 2 = 1 by the planes z = - y and z = 0.

 SOLUTION:

 

EXAMPLE 4:

Find the volume of the region in the first octant bounded by the coordinate planes and the surface z = 4 - x 2 - y.

SOLUTION:

I will integrate with respect to dz, then dy, and finally dx. z will go between 0 and 4 - x 2 - y. y will go between 0 and 4 - x 2, and x will go between 0 and 2.

 

EXAMPLE 5:

Find the average value of F (x, y, z) = x + y - z over the rectangular solid bounded by the coordinate planes and the planes x = 1, y = 1, and z = 2.

SOLUTION:

Here is the formula for the average value of a function.

The volume of the rectangular solid is (1)(1)(2) = 2.

EXAMPLE 6:

Evaluate the integral by changing the order of integration in an appropriate way.

SOLUTION:

As I look at the integrand of this triple integral, if I have to integrate with respect to x, I could not use a u-substitution, and integration by parts would be hairy. I think I will change the order of integration to by dy dx dz. By integrating with respect to y first, I will then have a u-substitution available when I integrate with respect to x next. Now, when x = 2y, then y = x/2. Here are the new integrals.

EXAMPLE 7:

Evaluate the integral by changing the order of integration in an appropriate way.

SOLUTION:

As I look at the integrand of this triple integral, integration with respect to x is fine, but the second integral is not straightforward. If I switch the order of dy and dz, then z will go between 0 and y 3, and y will go between 0 and 1.

As you can see by the examples that I have worked in this set of supplemental notes, half of the battle is setting up the triple integral. A sketch is useful in this step, or the use of computer software that will draw the surface for you. As with the case of double integrals, the order of integration does not change the answer. The thing that you should remember is that some orders of integration lead too more complicated integration. So changing the order of integration might simplify the integration. Work through these examples, and if you have any questions or problems, please feel free to contact me.

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